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    1. [KINCAID] DNA results for 136404
    2. Sue Liedtke
    3. The first panel for 136404 has been returned. The first 12 markers match Group A Apparent Ancestral Values except at marker 4 (DYS391) where he has an 11 instead of the AAV 12. 136404 believes descent from James Woodburn Kinkade b 1811 d 1862 m Margaret Kuhns 1839 of Westmoreland Co. PA. 15550 in Group A set 2a also claims descent from James Woodburn. 15550 does not have the 11 at marker 4. Every set in Group A except A-1a, which by definition does not have an 11 at this marker (though this may change if 33001 can prove to Thomas/Hannah Tincher), have incidences of an 11 at this marker. There are several proven parallel mutations to this value and several more that seem likely to have been parallel. Sue Liedtke

    10/17/2008 12:35:03
    1. Re: [KINCAID] DNA results for 136404
    2. Margie von Marenholtz
    3. Sue: What do you mean by PROVEN parallel mutations to the 11 marker value? Another question that would be useful to me understanding the Kincaid DNA Chart: Do you set up your groups by the first 12 markers only? As 136404 is the great grandson of James Woodburn Kinkade and 15550 is the great great grandson through a different son, would the distance removed from the mutual ancestor be a factor in a mutated value? Thank you for your insight. Margie ----- Original Message ----- From: "Sue Liedtke" <seleaml@actionnet.net> To: <kincaid@rootsweb.com> Sent: Friday, October 17, 2008 6:35 AM Subject: [KINCAID] DNA results for 136404 > The first panel for 136404 has been returned. The first 12 markers match > Group A Apparent Ancestral Values except at marker 4 (DYS391) where he has > an 11 instead of the AAV 12. > > 136404 believes descent from James Woodburn Kinkade b 1811 d 1862 m > Margaret > Kuhns 1839 of Westmoreland Co. PA. > > 15550 in Group A set 2a also claims descent from James Woodburn. 15550 > does > not have the 11 at marker 4. > > Every set in Group A except A-1a, which by definition does not have an 11 > at > this marker (though this may change if 33001 can prove to Thomas/Hannah > Tincher), have incidences of an 11 at this marker. There are several > proven > parallel mutations to this value and several more that seem likely to have > been parallel. > > Sue Liedtke > > > > To see the Kincaid of all spellings DNA chart in Excel: > http://freepages.genealogy.rootsweb.com/~adgedge/Research/April%202004/Kincaid%20%20DNA.xls > > > ------------------------------- > To unsubscribe from the list, please send an email to > KINCAID-request@rootsweb.com with the word 'unsubscribe' without the > quotes in the subject and the body of the message

    10/17/2008 04:05:39
    1. Re: [KINCAID] DNA results for 136404
    2. Peter A. Kincaid
    3. This is an interesting scenario. Sample 15550 is fairly close to my group and marker 4 is volatile in our group. Peter ----- Original Message ----- From: Margie von Marenholtz To: kincaid@rootsweb.com Sent: Friday, October 17, 2008 2:05 PM Subject: Re: [KINCAID] DNA results for 136404 Sue: What do you mean by PROVEN parallel mutations to the 11 marker value? Another question that would be useful to me understanding the Kincaid DNA Chart: Do you set up your groups by the first 12 markers only? As 136404 is the great grandson of James Woodburn Kinkade and 15550 is the great great grandson through a different son, would the distance removed from the mutual ancestor be a factor in a mutated value? Thank you for your insight. Margie ----- Original Message ----- From: "Sue Liedtke" <seleaml@actionnet.net> To: <kincaid@rootsweb.com> Sent: Friday, October 17, 2008 6:35 AM Subject: [KINCAID] DNA results for 136404 > The first panel for 136404 has been returned. The first 12 markers match > Group A Apparent Ancestral Values except at marker 4 (DYS391) where he has > an 11 instead of the AAV 12. > > 136404 believes descent from James Woodburn Kinkade b 1811 d 1862 m > Margaret > Kuhns 1839 of Westmoreland Co. PA. > > 15550 in Group A set 2a also claims descent from James Woodburn. 15550 > does > not have the 11 at marker 4. > > Every set in Group A except A-1a, which by definition does not have an 11 > at > this marker (though this may change if 33001 can prove to Thomas/Hannah > Tincher), have incidences of an 11 at this marker. There are several > proven > parallel mutations to this value and several more that seem likely to have > been parallel. > > Sue Liedtke >

    10/17/2008 09:13:04